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A convex mirror and a concave mirror each of focal length 10cm are placed coaxially. They are separated by 40cm and their reflecting surface face each other. A point object is kept on the principle axis at a distance X cm from the concave mirror such that final image after two reflections, first on the concave mirror, is on the object itself. Find the integer next to X.

Pranav Dabhade , 9 Years ago
Grade 12th pass
anser 1 Answers
Yashasvi yadav
Firstly we find v for concave mirror 
     V=uf/u-f => V=(-x)(-10)/-x+10 
        V =10x/10-x now if this term is positive then image will be formed behind concave mirror and the image formed by convex mirror will never lie on object .so this v is -ve   and v-40 will be u for convex mirror  so u=v-40=[-10x/10-x ]-40 = 30x-400 /10-x . 
 So for convex  mirror    u=30x-400/10-x ; v =-(40-x)=x-40 ;f=10 
     Applying mirror formula 
        V=uf/u-f    
         x-40=(30x-400 /10-x)(10) /[(30x -400)/10-x]-10 
      So we get quadratic on solving as 
      x²-60x+600=0 so X=25.35/2 =12.677 
 So integer next to x is 13 is the required answer ,regards 
Last Activity: 7 Years ago
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