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Grade: 12

                        

A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m/s.

3 years ago

Answers : (1)

Arun
24742 Points
							
 V = 340 m/s Distances between two nodes or antinodes⇒ λ/4 = 25 cm ⇒ λ = 100 cm = 1 m ⇒ n = v/λ = 340 Hz. 
3 years ago
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