To solve the problem of finding the distance of the final image of the bird from the bird itself, we need to consider the principles of reflection and the geometry involved. The bird is flying at a height of 2 meters above the water surface, and the swimming pool has a depth of 1 meter with a perfectly reflective bottom. Let's break this down step by step.
Understanding the Setup
We have a bird flying at a height of 2 meters above the water surface. The swimming pool is 1 meter deep, which means that the distance from the water surface to the bottom of the pool is 1 meter. Since the bottom of the pool is a perfectly reflective surface, we can think of the reflection of the bird as if there were an image of the bird below the water surface.
Calculating the Image Position
When the bird is at a height of 2 meters above the water, the image of the bird will be formed at an equal distance below the water surface due to the reflection. Since the water surface is at 0 meters (the reference point), the image of the bird will be at:
- Height of the bird above the water: 2 m
- Depth of the pool: 1 m
- Image of the bird below the water: -1 m (since it is below the water surface)
Thus, the image of the bird will be at a depth of 1 meter below the water surface, which means it is effectively at -1 m in our coordinate system. The total distance from the bird to its image can be calculated as follows:
Finding the Total Distance
The distance from the bird to the water surface is 2 meters, and the distance from the water surface to the image of the bird (which is 1 meter below the surface) is also 1 meter. Therefore, the total distance from the bird to its image is:
- Distance from the bird to the water surface: 2 m
- Distance from the water surface to the image: 1 m
Adding these distances gives us:
Total Distance = 2 m + 1 m = 3 m
Conclusion
Thus, the distance of the final image of the bird from the bird itself is 3 meters. Therefore, the correct answer is:
(A) 3 m
