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23. How many photons are emitted per second by a 5 mW laser source operating at 632.8 nm?


3 years ago

Arun
24738 Points
							the energy of each photon is =  E = hc / $\lambda$ = 6.63 * 10 –34 * 3 * 108 / 632.8 * 10 –9 = 3.14 * 10 –19  Jthe energy emitted per second by the laser is =  5 * 10 –3  Jhence totla no. of photons emitted per second  = 5 * 10 –3  J / 3.14 * 10 –19  J = 1.6 * 1016

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions