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2 pendulums of lenghts 1.44m and 1m start to swing together. The number of vibrations after which they will again start swinging together is.....

Vaishnavi Para , 7 Years ago
Grade 12
anser 2 Answers
Vikas TU

Last Activity: 7 Years ago

The day and age is straightforwardly relative to the square base of the length of pendulum 
T α √L 
T1/T2 = √L1/L2 
= √1.44/1 
= 12/10 
10T1 = 12T2 
After 10 motions they will swing together.

nehal

Last Activity: 5 Years ago

t is directly prop to root L hence by taking the square rooot of both the lengths u will get 1.2 and 1.0 .take the ratio of  both the time periods  the ratio will tell the ans that the longer one took 5 osc and shorter one will take 6 osc

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