IN A YOUNG DOULBLE SLIT EXPERIMENT THE INTENSITY AT CENTRAL MAXIMUM IS I. THE INTENSITY AT A DISTANCE B/4 AT CENTRAL MAXIMUM IS ( B IS THE FRINGE WIDTH)

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Askiitians Expert Soumyajit IIT-Kharagpur · Answer

Dear Arun Dash, Ans: B=&lambda;D/d................(1) Now at a distance B/4 from the central maxima the angle made by the light ray is &theta;, then tan&theta;=B/4D&asymp;&theta;&asymp;sin&theta; (as &theta; is very small).......................(2) Now path difference is d sin&theta;=d B/4D and hence phase difference is (2&prod;/&lambda;)d (&lambda;D/d)/4D=&prod;/2 Now intensity at this point is=Icos&sup2;(&prod;/2)=I/2 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Arun Dash !!! Regards, Askiitians Experts Soumyajit Das IIT Kharagpur

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IN A YOUNG DOULBLE SLIT EXPERIMENT THE INTENSITY AT CENTRAL MAXIMUM IS I. THE INTENSITY AT A DISTANCE B/4 AT CENTRAL MAXIMUM IS ( B IS THE FRINGE WIDTH)

IN A YOUNG DOULBLE SLIT EXPERIMENT THE INTENSITY AT CENTRAL MAXIMUM IS I. THE INTENSITY AT A DISTANCE B/4 AT CENTRAL MAXIMUM IS ( B IS THE FRINGE WIDTH)

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