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Coherent light thatthe wave lengths 600nm&470nm,passed throw the narrow slits separated by 0.3mm,and the interference pattren observed ona screen 5m from the slits.what is the distance on the screen the first-order bright fringes for two wave lengths?

Lakshman , 12 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To find the distance on the screen for the first-order bright fringes created by two different wavelengths of coherent light passing through narrow slits, we can use the principles of interference in wave optics. The formula we will use is derived from the double-slit interference pattern, which states that the position of the bright fringes on the screen can be calculated using the equation:

Understanding the Interference Pattern

The position of the m-th order bright fringe (where m is an integer representing the order of the fringe) is given by:

y = (m * λ * L) / d

Where:

  • y = distance from the central maximum to the m-th order bright fringe on the screen
  • m = order of the fringe (1 for first-order)
  • λ = wavelength of the light
  • L = distance from the slits to the screen
  • d = distance between the slits

Given Values

For this problem, we have:

  • Wavelengths: λ₁ = 600 nm = 600 x 10-9 m and λ₂ = 470 nm = 470 x 10-9 m
  • Distance between slits: d = 0.3 mm = 0.3 x 10-3 m
  • Distance to the screen: L = 5 m
  • Order of fringe: m = 1 (for first-order)

Calculating the Positions

Now, let's calculate the positions of the first-order bright fringes for both wavelengths.

For λ₁ = 600 nm

Substituting the values into the formula:

y₁ = (1 * 600 x 10-9 m * 5 m) / (0.3 x 10-3 m)

Calculating this gives:

y₁ = (600 x 5) / 0.3 = 10000 x 10-9 / 0.3 = 0.03333 m = 33.33 mm

For λ₂ = 470 nm

Now, substituting the second wavelength:

y₂ = (1 * 470 x 10-9 m * 5 m) / (0.3 x 10-3 m)

Calculating this gives:

y₂ = (470 x 5) / 0.3 = 7850 x 10-9 / 0.3 = 0.02617 m = 26.17 mm

Final Results

To summarize, the distances from the central maximum to the first-order bright fringes on the screen are:

  • For the wavelength of 600 nm: 33.33 mm
  • For the wavelength of 470 nm: 26.17 mm

This analysis shows how different wavelengths of light create distinct interference patterns, leading to varying positions of the bright fringes on the screen. Understanding this concept is crucial in optics and has applications in various fields, including physics and engineering.

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