Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A ray of light, after getting reflected twice from a hemispherical mirror of radius R, emerges parallel to the incident ray. The separation of the original incident ray and the final reflected ray is 1. R 2. R √ 2 3. 2R 4. R √ 3

A ray of light, after getting reflected twice from a hemispherical mirror of radius R, emerges parallel to the incident ray. The separation of the original incident ray and the final reflected ray is      


1. R                                                                2. R 2


 


3. 2R                                                             4. R 3

Grade:

1 Answers

MOHD SULEMAN
13 Points
4 years ago
The light incident and reflected will make angle of 90° each time. The tangent from both the reflected point meet and form 90° angle the perpendicular to tangent meet at centre and at centre the perpendiculars will form an angle of 90° . So the perpendiculars are radius and the distance can be calculated by pythagoras . From this the distance between incident and reflected light which are parallel to each other is R✓2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free