Last Activity: 12 Years ago
Dear Roopa,
your question is based on a simple formula,
heat energy required = mcT
mass=d.v=8933 . (.02)^3 = .0712 kg = 71.2 gm
mo of moles = 71.2 / 63.55 = 1.12 moles
c=24 j/k-mole.
T=20
H= (1.12) . 24 . 20
=537.6 Joules (ANS)
Regards.
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