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What curvature must be given to the bounding concave surface of refracting medium ( Refractive index = 3/2 ) for a virtual image at 40 cm of an object in this medium at a distance of 60 cm. The adjoining medium is air ( Refractive index = 1 ).
This question is very easy and is from Pradeep Physics Vol - II. But I doubt the way it is solved there :S
n1/u +n2/v=(n2-n1)/r
n1=1,n2=3/2,u=60cm, v=-40cm,r=?
substituting we get: 1/60 -3/80=1/2r
-5/240=1/2r,r=-24cm
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