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If the distance b/w the first maxima and the fifthminima of a double slit patternis 7mm ano the slits are separated by 0.15mm with the screen 50cm from theslits,then wavelength of the light used is
a.600nm
b.525nm
c.467nm
d.420nm
let d be distance between slits
X be distance between screen and slits
L be yhe wavelength
Distance of fifth minima from centre of screen = 9LX/(2d)
distance of 1st maxima from centre of screen = LX/d
=>distance between 1st maxima and fifth minima = 7LX/(2d)
=> 7LX/(2d) = 7mm
substituting values of x and d , we get L = 600 nm
ANS a.600nm
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