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how does the phase decrease as the wave moves in the direction.delta of phase angle is directly proportional to delta of displacementphase angle=-k x where k is propagation constant and -undicates decrease in phase in the direction of wave.plz explain

charitha .bvs , 13 Years ago
Grade 11
anser 1 Answers
SAGAR SINGH - IIT DELHI

Last Activity: 13 Years ago

Dear student,

The phase of a wave refers to a sinusoidal function such as the following:

x(t) = A\cdot \cos( 2 \pi f t + \theta )\,
y(t) = A\cdot \sin( 2 \pi f t + \theta ) = A\cdot \cos( 2 \pi f t + \theta -\pi/2),\,

where A, f, and \scriptstyle \theta are constant parameters. These functions are periodic with period \scriptstyle T = 1/f, and they are identical except for a displacement of \scriptstyle T/4 along the \scriptstyle t axis. The term phase can refer to several different things:

  • It can refer to a specified reference, such as \scriptstyle \cos( 2 \pi f t)\,, in which case we would say the phase of \scriptstyle x(t) is \scriptstyle \theta, and the phase of \scriptstyle y(t) is \scriptstyle \theta -\pi/2.
  • It can refer to \scriptstyle \theta, in which case we would say \scriptstyle x(t) and \scriptstyle y(t) have the same phase but are relative to different references.

 

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Sagar Singh

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