Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

how does the phase decrease as the wave moves in the direction.delta of phase angle is directly proportional to delta of displacement phase angle=-k x where k is propagation constant and -undicates decrease in phase in the direction of wave.plz explain

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

The phase of a wave refers to a sinusoidal function such as the following:

$x(t) = A\cdot \cos( 2 \pi f t + \theta )\,$
$y(t) = A\cdot \sin( 2 \pi f t + \theta ) = A\cdot \cos( 2 \pi f t + \theta -\pi/2),\,$

where A, f, and $\scriptstyle \theta$ are constant parameters. These functions are periodic with period $\scriptstyle T = 1/f$, and they are identical except for a displacement of $\scriptstyle T/4$ along the $\scriptstyle t$ axis. The term phase can refer to several different things:

• It can refer to a specified reference, such as $\scriptstyle \cos( 2 \pi f t)\,$, in which case we would say the phase of $\scriptstyle x(t)$ is $\scriptstyle \theta$, and the phase of $\scriptstyle y(t)$ is $\scriptstyle \theta -\pi/2$.
• It can refer to $\scriptstyle \theta$, in which case we would say $\scriptstyle x(t)$ and $\scriptstyle y(t)$ have the same phase but are relative to different references.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.