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OTP to be sent to Change
dear nehal i am giving u hint for this but solve by yourself ,
wrt to lens , there are two positions of object which are extream positions of this motion of particle ...
let these points are P,Q then
P = 3f+a , Q = 3f-a
now , inage corresponding to P & Q is P1 , Q1
apply lens formula for both images & find P1& Q1 then
(P1-Q1) = distance bw two extream ends
ans is {2f2a/4f2-a2}
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