Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A paralel beam is incident on a prism.the prism has vertical angle 4`and base angles 88`&88` respectively. A Plane miror is placed verticaly on the other side of incoming rays. By what angle shld the miror be rotated sop that light returns back to its original path.(refractive index of prism is 1.5) {ans.....2 degree}
draw a prism ABC with verticle angle A =4 degree...
now draw a plane mirror which is inclined at @ with horizontal plane...
the ray returns to its original path if & if only when the ray coming out from the prism is normal to the mirror...
now draw this diagram
we have d(angle of deviation) = (n-1)A (formula)
=2o ............1 (n=3/2)
let ray intersects the prism at X & comes out , & intersects plane mirror at Y and is reflected back ,
now extend the parallel ray which was incident on prism, so that it touches the plane mirror at point Z...
now we have XYZ as a right angled triangle....
angle X = angle of deviation
angle Z = @ (from diagram)
angle Y =90
X+Y+Z =180
d + @ + 90 = 180
d+@ = 90
@ = 88o ...................2
initially mirror was at 90o , but when its angle is 88o our purpose is solved so it should be rotated through (90-88)=2o
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !