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Suppose you are inside the water in a swimming pool near an edge. A friend is standing on the edge. Do you find your friend taller or shorter than his usual height?
consider an object placed outside water surface , if observer is in water then he will see the image of object formed after refration through water ....
let initially object is placed at a distance x from surface
for refraction from rarer to denser medium (u is the refractive index of medium)
u/v - 1/x =u-1/R (refractive index of air is 1)
R=infinity
u/v=1/x
v=ux (u>1)
so v>u
thus the height of friend who is outside is greater than original ...
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