A point object lies inside a transparent solid sphere of radius 20 cm and of refractive index n=2. When the object is viewed from the air through the nearest surface, it is seen at a distance 5 cm from the surface. Find the apparent distance of the object when it is seen through the farthest curved surface.

Dear Rohan,

Ans:- From the basic formulae of refraction we know that,

n2/v - n1/u = (n2 - n1)/R

 Now it is given that v= -5cm. n2=1 n1=2

solving we get, u= - 40/3 cm

Now if we see from the other side, then u= - 80/3 cm. v=? and R=+20 cm

solving we get, v=-8 cm. Hence we will see it at a distance of 8 cm from that surface.

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From the basic formulae of refraction we know that,n2/v - n1/u = (n2 - n1)/R Now it is given that v= -5cm. n2=1 n1=2solving we get, u= - 40/3 cmNow if we see from the other side, then u= - 80/3 cm. v=? and R=+20 cmsolving we get, v=-8 cm. Hence we will see it at a distance of 8 cm from that surface.