when displacement is one half of amplitude. ratio kinetic to potential energy?

Question

Vikas TU · Answer

Dear Student,

If the question is of SHM which is highly likely to be, then the answer is
Potential energy=U=kx²/2 (x is the displacement)
Total energy= T=kA²/2 (A is the amplitude)
U=kA²/8
T=kA²/2
Kinetic energy=K=3kA²/8

Ratio=K/U
=3:1

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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when displacement is one half of amplitude. ratio kinetic to potential energy?

when displacement is one half of amplitude. ratio kinetic to potential energy?

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