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# What should be tension applied to a wire of length 1m and mass 10g if it has to vibrate with fundamental frequency of 50 Hz

Arun
25763 Points
3 years ago
Dear Akshay

mass m = 10 gm = 0.01
n = (1/2L) $\sqrt$(T/m)
Now
50 = 1/2 $\sqrt$(T/0.01)
100² = T/0.01
10000*0.01 = T
T = 100 N

Regards
Phanindra
226 Points
3 years ago
$n = 1/2l \sqrt(T/\mu )...$
Here both T and μ are under square root...
T = tension in the string (newton)
μ = linear mass density = mass/length..
...(kg per meter)
l = length of the string...(in meters)
Now substitute the values to get Tension in the string..