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Velocity of air is 320 m/s a pipe is closed at one end has length of 1m neglecting end correction then the air column can resonate with a frequency of


3 years ago

Jay Sawant
37 Points
							Here the pipe is opened at one end and closed at other end.Therefore, at open end the displacement wave will always have antinode while at the closed end the displacement wave will always have node.During its fundamental freq , wavelength=4l(l=length of pipe)f = v/4lDuring 1st Overtone Wavelength=4/3lf = 3(v/4l)..Now doing the same for 2nd,3rd and so on overtonesFrequency=n(v/4l) n belongs to odd integers(n>0).These are called as odd harmonics.

3 years ago
Arun
24742 Points
							For a closed pipe, frequrncies of harmonics are$\LARGE \nu$1 = v/4L = 320/4 = 80 Hz$\LARGE \nu$2 = 3v/4L = 3 *80 = 340 Hz$\LARGE \nu$3 = 5v/4L = 5*80 = 400 HzSimilarily we can also get some more frequencies

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions