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Two transparent slabs having equal thickness but different refractive indices μ1 and μ2 are pasted side by side to form a composite slab. This slab is placed just after the double slit in a Young’s experiment so that the light from one slit in a young’s experiment so that the light from the other slit goes through the other material. What should be the minimum thickness of the slab so that there is a minimum at the point P0 which is equidistant from the slits?

Two transparent slabs having equal thickness but different refractive indices μ1 and μ2 are pasted side by side to form a composite slab. This slab is placed just after the double slit in a Young’s experiment so that the light from one slit in a young’s experiment so that the light from the other slit goes through the other material. What should be the minimum thickness of the slab so that there is a minimum at the point P0 which is equidistant from the slits?

Grade:10

1 Answers

Jitender Pal
askIITians Faculty 365 Points
7 years ago
Sol. The change in path difference due to the two slabs is (μ base 1 – μ base 2)t (as in problem no. 16). For having a minimum at P base 0, the path difference should change by λ/2. So, ⇒ λ/2 = (μ base 1 – μ base 2)t ⇒ t = λ/2(μ base 1 – μ base 2)

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