# Two stationary sources each emitting waves of wave length λ. An observer moves from one source to other with velocity u. Then number of beats heared by him is?

12Myra Kothari
17 Points
5 years ago
f1= (v-u​)f/v
f2= (v+u)f/v
Now beat frequency = f2-f1 = $\frac{(v+u)f}{v} - \frac{(v-u)f}{v} = \frac{2uf}{v}= \frac{2u}{l}$
here l = wavelength

Rishi Sharma