Jitender Pal
Last Activity: 10 Years ago
SOL. Given that, d = 1 cm = 10^–2 m, λ = 5 * 10^–7 m and D = 1 m
a) Separation between two consecutive maxima is equal to fringe width.|
So, β = λD/d = 5 * 10^-7 * 1/10^-2m = 5 * 10^-5 m = 0.05 mm.
b) When, β = 1 mm = 10^-3 m
10^-3m = 5 * 10^-7 * 1/D ⇒ D = 5 * 10^-4 m = 0.50 mm.