Deepak Patra
Sol. . mA = 1.2 * 10–2 kg/m, TA = 4.8 N
⇒ VA = √T /m = 20 m/s
mB = 1.2 * 10–2 kg/m, TB = 7.5 N
⇒ VB = T /m = 25 m/s
t = 0 in string A
t1 = 0 + 20 ms = 20 * 10–3 = 0.02 sec
In 0.02 sec A has travelled 20 * 0.02 = 0.4 mt
Relative speed between A and B = 25 – 20 = 5 m/s
Time taken for B for overtake A = s/v = 0.4/5 = 0.08 sec