two bodies A and B starts from rest from the same point with a uniform acceleration of 2m/s^2. If B starts one second later,then the two bodies are seperated at the end of the next second by?

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Arun · Answer

In two seconds, the body `A` has moved 4 meter. {That is applying the formula S=ut+1/2at^2.} The particle `B` starts one second later and therefore, has travelled for one second only. Applying the same formula, the distance moved is 1 meter.. Now, provided that both the particles are moving in the same direction, this distance between them would be 4-1 = 3 meters.

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two bodies A and B starts from rest from the same point with a uniform acceleration of 2m/s^2. If B starts one second later,then the two bodies are seperated at the end of the next second by?

two bodies A and B starts from rest from the same point with a uniform acceleration of 2m/s^2. If B starts one second later,then the two bodies are seperated at the end of the next second by?

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two bodies A and B starts from rest from the same point with a uniform acceleration of 2m/s^2. If B starts one second later,then the two bodies are seperated at the end of the next second by?

two bodies A and B starts from rest from the same point with a uniform acceleration of 2m/s^2. If B starts one second later,then the two bodies are seperated at the end of the next second by?

1 Answers

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Other Related Questions on Wave Motion

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