Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The time lag between 2 particles vibrating in a progressive wave separated by a distance 20m is 0.02s . The wave velocity of he frequency of the wave is 500hz,is

The time lag between 2 particles vibrating in a progressive wave separated by a distance 20m is 0.02s . The wave velocity of he frequency of the wave is 500hz,is
 

Grade:12

2 Answers

Nallamilli Veena Madhuri
13 Points
4 years ago
Velocity=frequency×wavelength=500× (1/500×0.02)×20=20/0.02=1000m/s , how to find length,for 0.02sec---20m and for T=1/f=1/500------? ?=1/(500×0.02) ×20m= wavelength
Karthik
13 Points
2 years ago
 Here , Velocity = distance covered / time taken
 c=20/0.02=1000ms-1 . So , wave velocity is 1000ms-1 . This can be bone in other way too by converting the Hz value 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free