the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2

Question

Khimraj · Answer

Total energy of of particle executing shm T.E.= max kinetic energy = ½ m ω 2 a 2 At extreme position kinwtic energy will be zero So Potential energy at extreme position P.E. = T.E. = ½ m ω 2 a 2 = e(given) then Kinetic energy at y = a/2 K = ½ mω 2 [a 2 – a 2 /4] So, K.E. = ¾ ( ½ m ω 2 a 2 ) K..E = ¾ e Hope it clears. If you like answer then please approve it.

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the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2

the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2

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the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2

the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2

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