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Grade: 12th pass
        the potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2
9 months ago

Answers : (1)

Khimraj
2468 Points
							
Total energy of of particle executing shm T.E.= max kinetic energy = ½ mω2a2
At extreme position kinwtic energy will be  zero So Potential energy at extreme position P.E. = T.E. = ½ mω2a2 = e(given)
then Kinetic energy at y = a/2
K = ½ mω2[a2 – a2/4]
So, K.E. = ¾ (½ mω2a2)
K..E = ¾ e
Hope it clears. If you like answer then please approve it.
9 months ago
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