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Grade: 12th pass
        
The phase difference between two points separated by 1 m in a wave of frequency 120hz is 90 degree .The wave velocity will be …....?
2 years ago

Answers : (1)

Arun
23755 Points
							
Dear Gaurav
 
Path difference \Delta = \lambda \phi/2\pi
 
1 = (\lambda/2\pi) * (\pi/2)
\lambda = 4 m
 
Hence
V = n* \lambda = 120*4 = 480 m/sec.
 
Regards
Arun (askIITians forum expert)
2 years ago
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