#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# The phase difference between two points separated by 1 m in a wave of frequency 120hz is 90 degree .The wave velocity will be …....?

Arun
25763 Points
3 years ago
Dear Gaurav

Path difference $\Delta$ = $\lambda \phi$/2$\pi$

1 = ($\lambda$/2$\pi$) * ($\pi$/2)
$\lambda$ = 4 m

Hence
V = n* $\lambda$ = 120*4 = 480 m/sec.

Regards
Rishi Sharma
8 months ago
Dear Student,

Path difference Δ = λɸ/2π
1 = (λ/2π)*(π/2)
λ = 4 m
Hence
V = n*λ = 120*4 = 480 m/sec.

Thanks and Regards