the period of a simple pendulum is 2 s and the amplitude of vibration is 5 cm.write down the equation of its motion.what will be the displacement and velocity of particle after 1.5 s

Question

Suresh Sonkar · Answer

suppose particle starts from the mean position: The equation of motion will be x = Asinωt Where x is displacement at any time t and A is amplitude and ω is the angular velocity Given time period T = 2 sec So ω = 2π/T = 2π/2 = π Given amplitude A = 5 cm So the equation of motion will be: x = 5sin(πt)…………………………(1) Displacement at t = 1.5 sec x = 5sin( π(1.5)) = 5sin(1.5π) = -5cm at this point velocity of the particle : differentiation equation1 wrt to time ‘t’ v = 5*π cos(πt) = 5*π cos(1.5π) = 0 Means particle is at extreme position

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

the period of a simple pendulum is 2 s and the amplitude of vibration is 5 cm.write down the equation of its motion.what will be the displacement and velocity of particle after 1.5 s

the period of a simple pendulum is 2 s and the amplitude of vibration is 5 cm.write down the equation of its motion.what will be the displacement and velocity of particle after 1.5 s

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Wave Motion

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship