The frequency of note emitted by a source changes by 20% as it approaches observer.As it recedes away from him the apparent frequncy will be?
prema , 6 Years ago
Grade 12th pass
2 Answers
prema
Last Activity: 6 Years ago
mein ne is question ko post kiya tha.par abtak kuch answer nahi mila.jab meine askiitans mein login kiya tha tab yah sochlar kiya tha ki yahanke teachers mere is question par gaur karrnge aur mujhe answe
r denge.lekin abtak meine jitne hi questions
dale hai muje koi javab nahi mila hai.yeh
mein ne nahi socha tha
Arun
Last Activity: 6 Years ago
Dear student
n(120/100) = (v / v – vs) *n
1.2 V – 1.2 Vs = V
0.2 V = 1.2 Vs
Vs = V/6
when it recedes away
(100 – x / 100) * n = (V / V + Vs)*n
1 – x /100 = 6/7
x = 14.3 %
hence 14.3% different from actual frequency
Regards
Arun
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free