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The equilibrium position of an object in an oscillating system is always the point where
(A) x = 0. (B) vx = 0.
(C) ax = 0. (D) px = 0.

Amit Saxena , 10 Years ago
Grade upto college level
anser 1 Answers
Navjyot Kalra

Last Activity: 10 Years ago

The correct option is (A).
The particle moves toward its equilibrium position at x = 0. The force must always act to restore the particle to its equilibrium position. Therefore the equilibrium position of an object in an oscillating system is always the point where x = 0. Thus option (A) is correct.

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