The equilibrium position of an object in an oscillating system is always the point where (A) x = 0. (B) v x = 0. (C) a x = 0. (D) p x = 0.

Question

Navjyot Kalra · Answer

The correct option is (A).
The particle moves toward its equilibrium position at x = 0. The force must always act to restore the particle to its equilibrium position. Therefore the equilibrium position of an object in an oscillating system is always the point where x = 0. Thus option (A) is correct.

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The equilibrium position of an object in an oscillating system is always the point where (A) x = 0. (B) v x = 0. (C) a x = 0. (D) p x = 0.

The equilibrium position of an object in an oscillating system is always the point where
(A) x = 0. (B) v_x = 0.
(C) a_x = 0. (D) p_x= 0.

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The equilibrium position of an object in an oscillating system is always the point where (A) x = 0. (B) v x = 0. (C) a x = 0. (D) p x = 0.

The equilibrium position of an object in an oscillating system is always the point where(A) x = 0. (B) vx = 0.(C) ax = 0. (D) px = 0.

1 Answers

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The equilibrium position of an object in an oscillating system is always the point where
(A) x = 0. (B) v_x = 0.
(C) a_x = 0. (D) p_x= 0.