The distance between two points differing in phase by 60 on a wave having a frequency of 500hz and velocity of 360m/s is......?

Question

Saurabh Koranglekar · Answer

Vikas TU · Answer

Dear student

k = speed/frequency

=> k =36/50

now phase difference = (2∏/k )* path difference

60 = (360/36) * 50 * path difference

distance bewtween two nearest points is = path difference = 6/50 metre

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The distance between two points differing in phase by 60 on a wave having a frequency of 500hz and velocity of 360m/s is......?

The distance between two points differing in phase by 60 on a wave having a frequency of 500hz and velocity of 360m/s is......?

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The distance between two points differing in phase by 60 on a wave having a frequency of 500hz and velocity of 360m/s is......?

The distance between two points differing in phase by 60 on a wave having a frequency of 500hz and velocity of 360m/s is......?

2 Answers

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