The angular displacement of simple pendulum is given by Theta= 0.1 pi sin(2 pi t +pi/5) The mass of bob is 0.4 kg Calculate 1) length of simple pendulum 2) velocity at 0.25s

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Vikas TU · Answer

Dear student Please type the SHM equation correctly , You have given pi in amplitude term. We will happy to help you . Good Luck cheers

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The angular displacement of simple pendulum is given by Theta= 0.1 pi sin(2 pi t +pi/5) The mass of bob is 0.4 kg Calculate 1) length of simple pendulum 2) velocity at 0.25s

The angular displacement of simple pendulum is given by
Theta= 0.1 pi sin(2 pi t +pi/5)
The mass of bob is 0.4 kg
Calculate
1) length of simple pendulum
2) velocity at 0.25s

1 Answers

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The angular displacement of simple pendulum is given by Theta= 0.1 pi sin(2 pi t +pi/5) The mass of bob is 0.4 kg Calculate 1) length of simple pendulum 2) velocity at 0.25s

The angular displacement of simple pendulum is given byTheta= 0.1 pi sin(2 pi t +pi/5)The mass of bob is 0.4 kgCalculate 1) length of simple pendulum2) velocity at 0.25s

1 Answers

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The angular displacement of simple pendulum is given by
Theta= 0.1 pi sin(2 pi t +pi/5)
The mass of bob is 0.4 kg
Calculate
1) length of simple pendulum
2) velocity at 0.25s