Show that if the room temperature changes by a small amount from T to T + ∆T, the fundamental frequency of an organ pipe changes from v to v + ∆v, where ∆v/v = 1/2 ∆T/T.

Question

Aditi Chauhan · Answer

Sol. V base rod = ?, V base air = 340 m/s, L base r = 25 × 10^–2, d base 2 = 5 × 10^–2 metres V base r/V base a ⇒ V base r = 340 * 25 * 10^-2 * 2/5 * 10^-2 = 3400 m/s.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Show that if the room temperature changes by a small amount from T to T + ∆T, the fundamental frequency of an organ pipe changes from v to v + ∆v, where ∆v/v = 1/2 ∆T/T.

Show that if the room temperature changes by a small amount from T to T + ∆T, the fundamental frequency of an organ pipe changes from v to v + ∆v, where ∆v/v = 1/2 ∆T/T.

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Wave Motion

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship