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Grade:Upto college level

2 Answers

Navneet kumar
37 Points
7 years ago
I1/I2= 4/1 so a1/a2 = 2/1 so amax/ amin = 2+1/2-1 = 3/1 so Imax/ Imin= 9/1 Now loudness L = 10 log(I/I0) So difference of loudness = L1-L2 = 10 log (9I/I) = 10 log9 = 20 log3
Navneet kumar
37 Points
7 years ago
f=y/2l =3800/2*1=1900 hz

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