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Please answer this question briefly please ??????????????????????????????

Please answer this question briefly please ??????????????????????????????

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Grade:12th pass

1 Answers

Arun
25763 Points
2 years ago
For pulses to cancel out, 
y1 + y2 = 0 
=> 5 / [(3x - 4t)^2 + 2] - 5 / [(3x + 4t - 6)^2 + 2] = 0 
=> [(3x + 4t - 6)^2 + 2] - [(3x - 4t)^2 + 2] = 0 
=> (3x + 4t - 6)^2 - (3x - 4t)^2 = 0 
=> (3x + 4t - 6 + 3x - 4t) (3x + 4t - 6 - 3x + 4t) = 0
=> (6x - 6) (8t - 6) = 0 
=> (x - 1) (4t - 3) = 0 
=> x - 1 = 0 or 4t - 3 = 0 
=> x = 1 m or t = 0.750 sec.

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