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Plane sound wave of frequency 500 Hz fall normally on a smooth wall.At what distance from the wall will the air particles have maximum and minimum amplitude of vibration and the velocity of sound in air may be taken as 340 meter per second

Fame , 6 Years ago
Grade 12
anser 1 Answers
Arun
 
Shortest distance should be lambda/4
 
Now
Lambda = v/f = 330/500 = 0.66
 
 
Hence distance = 0.66/4 = 0.165 m
 
Hope it helps
Last Activity: 6 Years ago
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