Kevin Nash
Last Activity: 10 Years ago
Sol. For strong transmission, 2 μd = nλ ⇒ λ = 2μd/n
Given that, μ = 1.33, d = 1 * 10^-4 cm = 1 * 10^-6 m.
⇒ λ = 2 * 1.33 * 1 * 10^-6/n = 2660 * 10^-9/n m
When, n = 4, λ base 1 = 665 nm
n = 5, λ base 2 =532 nm
n = 6, λ base 3 = 443 nm