Arun
Last Activity: 6 Years ago
Dear Vivek
Let the distance to the top be d.therefore, the speed of the man with escalator not moving = (d/1) m/min.therefore the speed of the escalator with the man at rest = (d/3) m/minWhen both the man and the escalator are moving, effective speed= (d/3 + d) m/min =(4d/3)m/minTherefore time taken when both man and escalator are moving = distance / speed = d/(4d/3) min. = 3/4 min = 45 seconds
Regards
Arun (askIITians forum expert)