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initially spring is compressed by distance x0 from equilibriuim position at this compression block is given velocity (3k/m)^1/2 x0 so that compression increase and block start shm spring constant =k equation of motion is. i got how amplitude came but not phase epoch. ans.y=2x0sin[(k/m)^1/2t+ pi/6]

initially spring is compressed by distance x0 from equilibriuim position at this compression block is given velocity (3k/m)^1/2 x0 so that compression increase and block start shm spring constant =k equation of motion is.
i got how amplitude came but not phase epoch.
ans.y=2x0sin[(k/m)^1/2t+ pi/6]

Grade:12th pass

1 Answers

Vikas TU
14149 Points
2 years ago
Each of these constants carries a physical meaning of the motion: A is the amplitude (maximum displacement from the equilibrium position), ω = 2πf is the angular frequency, and φ is the initial phase. By definition, if a mass m is under SHM its acceleration is directly proportional to displacement.

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