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# in youngs experiment two coherent sources placed 0.90mm  apart and fringes are observed one metre away. if it produces the second dark fringe at a distance of 1mm from the central fringe , the wavelenght of monochromatic light used would be  options a. 60*10-4cmb. 10*10-4cmc. 10*10-5cmd. 6*10-5cm

Arun
25763 Points
3 years ago
Dear student

Distance of nth dark fringe from central fringe

Xn = (2n -1)$\lambda$D/2d

Hence X2 = 3 *$\lambda$ D/2d

1 * 10^-3 = 3 * $\lambda$ * 1/2 * 0.9 * 10^-3

$\lambda$ = 6 * 10^-5 cm

Hence option D is correct.