cool matrix
Last Activity: 8 Years ago
The resultant fringewidth orbandwidth will decrease by putting the entire setup in water. This is bcoz u know that lambda(wavelength) decreases in water than air keeping frequency constant as speed changes. It becomes (lamda)/u where u is refractive index of water.Thats why fringe width given by (lamda)D /d gets changed to (lambda)D/ud. where `u` is refractive index of water. so your answer will be 2/(4/3) which is 3/2. Hope u got it.