Jitender Pal
Last Activity: 10 Years ago
Sol. a) According to the data
λ/4 = 16.5 mm ⇒ λ = 66 mm = 66 × 10^–6=3 m
⇒ n = V/λ = 330/66 * 10^-3 = 5 kHz.
b) l base minimum = K(A base 1 0 A base 2)^2 = l ⇒ A base 1 – A base 2 = 11
l base minimum = K(A base 1 0 A base 2)^2 = 9 ⇒ A base 1 + A base 2 = 31
So, A base 1 + A base 2/A base 1 + A base 2 = 3/4 ⇒ A base 1/ A base 2 = 2/1
So, the ratio amplitudes is 2.