Kevin Nash
Last Activity: 10 Years ago
Sol. In the given Young’s double slit experiment,
μ = 1.6, t = 1.964 micron = 1.964 * 10^–6 m
We know, number of fringes shifted = (μ – 1)t/λ
So, the corresponding shift = No. of fringes shifted * fringe width
= (μ – 1)t/λ * λD/d = (μ – 1)tD/d …..(1)
Again, when the distance between the screen and the slits is doubled,
Fringe width = λ(2D)/d …..(2)
From (1) and (2), (μ – 1)tD/d = λ(2D)/d
⇒ (μ – 1)t/λ = (1.6 - 1) * (1.964) * 10^-6/2 = 589.2 * 10^-9 = 589.2 nm.