MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
in a population that is in hardy weingberg  equilibrium 16 percent of individual show recessive trait. what is frequency of dominant allele in population? a. 0.84
one year ago

Answers : (1)

Arun
22558 Points
							

If 16% of the population shows the recessive trait, then that figure (16%) accounts for all the homozygous (hh) recessive individuals in that population.

This is one of most classical cases of applying a quadratic equation to the life sciences. One must also understand that this is a classical “Mendelian” genetics problem.

Heterozygyous individuals (Hh) [inferably] do not express the homozygous recessive condition for this particular allele, but follow a traditional dominant expression. Classical genetics relies on these formally declared values.

The remaining 84% of the population does not show for the recessive trait.

That 84% includes both homozygous “purely” dominant (HH) or heterozygous (Hh) “hybrid” individuals for that allele, according to classical genetics and Punnet squares.

one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details