Navjyot Kalra
Last Activity: 11 Years ago
Sol. Given that, d = 1 mm = 10^–3 m, D = 1 m.
So, fringe with = Dλ/d = 0.5 mm.
a) So, distance of centre of first minimum from centre of central maximum = 0.5/2 mm = 0.25 mm
b) No. of fringes = 10 / 0.5 = 20.