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If two mutually perpendicular simple harmonic motion of same amplitude, frequency and having zero phase difference superimpose on a particle then its resultant path will be

Khushboo , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

If   y_{1} = a_{1}\sin\omega t andy_{2} = a_{2}\sin(\omega t + 0) = a_{2}\sin{\omega t}

\Rightarrow \frac{y_{1}^{2}}{a_{1}^{2}} + \frac{y_{2}^{2}}{a_{2}^{2}} - \frac{2y_{1}y_{2}}{a_{1}a_{2}} = \Rightarrow y_{2} = \frac{a_{2}}{a_{1}}y_{1}

This is a equation of straight line.

 

Resultant equation of two perpendicular SHM when δ = 0 -

Resultant equation

y= \frac{A_{2}}{A_{1}}.x

 

- wherein

It is a straight line with slope

\frac{A_{2}}{A_{1}}

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