Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
If in a stationary wave the amplitude at antinode is 4cm. The amplitude at midway of node and antinode is?
A node has a zero amplitude and an anti-node has a maximum amplitude. So, if the amplitude at anti-node is 4 cm, therefore the exact midway between node and anti-node will be at 2 cm.
A/=2ASin kxk= 2 pie/lambdax=lambda/8 [distance b/w node and antinode = lamda/2 … so distance b/w amplitude and 0 =lambda/4.....and mid point of these two points= lambda/8]2A=4 [given]4Sin [2pie/lambda.×lambda/8]4sin[pie/4]= 4/21/2 = 2*21/2cm
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -