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Hi can you help me out..I don`t know how to approach these kind of questions

Hi can you help me out..I don`t know how to approach these kind of questions

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Grade:12

1 Answers

Sandeep Bhamoo
443 Points
3 years ago
In steady state current through a capacitor is always 0 hence the only citcuit to be cisidered comprises of two resistance 2 and 3 ohm in parallel+ one resistance of 2.8 ohm in series ,hence net resistance in steady state is4 ohm. Hence current is =v/i= 6/4=1.5 ampere. Please fo approve my answer if correct

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