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Grade: 12
        
Help me out with this sum plzzzzz plzz_zzzzzzzzzzzzzzzzzzzxzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzxxxxxxxxxxxxx
one month ago

Answers : (1)

Pooja
126 Points
							

Here mass A will slide down and mass B will move above
Let the Tension in string be T and acceleration of system be a

For mass B
mBa = mBg*sin(37) - T
For mass A
mAa = T - mAg*sin(53)

So ,
mBg*sin(37) - mBa = mAa +  mAg*sin(53)


10×10×3/5 -10a = 2a + 2×10 ×4/5

60 - 10a = 2a + 16

a = 44/12 =3.67m/s2

29 days ago
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Course Features

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  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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