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Fundamental frequency of closed organ pipe is 50hz. The frequency of second overtone is?

shy , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear student
 
Fundamental frequency of a closed pipe = v(sound) /4L 
Given, = 50 Hz 
v(sound) /4L =50Hz
Frequency of second overtone is :
= 5 {v(sound)/4L} 
= 5 x fundamental frequency 
= 5 x 50 Hz = 250 Hz
 
 
Regards
Arun (askIITians forum expert)
Last Activity: 7 Years ago
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